40+ Force and Laws of Motion Class 9 Numericals

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Here are a few Important Force and Laws of Motion Class 9 Numerical for practice. These Force and Laws of Motion Class 9 Numerical will help you make better concepts.

Force and Laws of Motion Class 9 Numerical

Note: Before looking for the solution, first try yourself, and when it becomes very difficult or if you want to check your solution, only then open the answer and explanation.

I have also provided some questions from your books themselves but with changes in the data. So try solving those questions and put your answer in the comment box. I will surely react to your answer.

Force and Laws of Motion Class 9 Numerical

Before you solve the questions, let’s revise the important formulas that you read in the chapter Force and Laws of Motion.

Class 9 Important Force and Laws of Motion Formula

  • Force = mass × acceleration
  • Force = rate of change in momentum = (Final momentum – Initial Momentum)/time
  • Momentum (p) = mass × velocity
  • Chane in Momentum = mass × (final velocity – Initial Velocity) = m×(v-u)
  • Impulse = Force × time
  • Impulse = change in momentum = mass×(v-u)
  • Conservation of Momentum = m1u1+m2v2=m1v1+m2v2

Question 1.

A constant force acts on an object of mass 5 kg for a duration of 2 s. It increases the object’s velocity from 3 m/s to 7 m/s. Find the magnitude of the applied force. Now, if the force was applied for a duration of 5 s, what would be the final velocity of the object?

Click for Answer/Explanation

F = m(v-u)/t

Substitution of values in this relation gives F = 10 N

The final velocity can be calculated by

v= u+at = 13 m/s.

Question 2.

Which would require a greater force – accelerating a 2 kg mass at 5 m/s² or a 4 kg mass at 2 m/s²?

Click for Answer/Explanation

Use

F = ma

and solve it

Question 3.

A motorcar is moving with a velocity of 108 km/h and it takes 4 s to stop after the brakes are applied. Calculate the force exerted by the brakes on the motorcar if its mass along with the passengers is 1000 kg.

Click for Answer/Explanation

Initial velocity- 108 km/h = 30 m/s, Final Velocity = 0 m/s

Use the Equation of motion and find a = -30/4 = -7.5 m/s2

Now, F = ma

Solve and get F = -7500 N (-ve sign means, the force by brakes applied is opposite of the direction of motion)

Question 4.

A body of mass 1 kg undergoes a change of velocity of 4 m/s in 4 s what is the force acting on it?

Click for Answer/Explanation

Δv= 4m/s, t= 4 s, m=1 kg

Acceleration is given by, a= Δv/t

a= 1 m/s²

Now the force is given by

F= ma

F= 1 N

Question 5.

A driver accelerates his car first at the rate of 4 m/s² and then at the rate of 8 m/s². Calculate the ratio of the forces exerted by the engines.

Click for Answer/Explanation

F1=ma1 and F2= ma2

So, Ratio of force exerted is given by = F1/F2= ma1/ma2 = a1/a2=1:2

Question 6.

A cricket ball of mass 0.20 kg is moving with a velocity of 1.2 m/s. Find the Impulse on the ball and the average force applied by the player if he is able to stop the ball in 0.10 s?

Click for Answer/Explanation

Impulse= Change in momentum

I = Δp = mΔv = -0.24 kgm/s

Also, Impulse = F×t

Put the value of t and get the Force

Video Solution of Question 6.

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Question 7.

Two objects of masses of 100 gm and 200 gm are moving in along the same line and direction with velocities of 2 m/s and 1 m/s respectively. They collide and after the collision, the first object moves at a velocity of 1.67 m/s. Determine the velocity of the second object.

Click for Answer/Explanation

By the law of conservation of momentum,

m1u1+m2u2 = m1v2+m2v2

On substituting the values

0.1×2+0.2×1=0.1×1.67+0.2v2

Or, v2=1.165 m/s

It will move in the same direction after the collision

Question 8.

An object of mass 1 kg traveling in a straight line with a velocity of 10 m/s collides with and sticks to a stationary wooden block of mass 5 kg. Then they both move off together in the same straight line. Calculate the total momentum just before the impact and just after the impact. Also, calculate the velocity of the combined object.

Click for Answer/Explanation

Initial Momentum

p_{1}=m_{1}v_{1}+m_{2}v_{2}

p1=10 kgm/s = 10 kgm/s

Now after the collision, they stick together to move with velocity V

Final Momentum

p2= (m1+m2)V = 6V

Now As per the law of conservation of Momentum, the external force is absent

Initial Momentum = Final Momentum

p1 = p2

10 = 6V

V=1.67 m/s

Now

p2 =6V= 10 kg-m/s

Question 9.

A man weighing 60 kg runs along the rails with a velocity of 18 km/h and jumps into a car of mass 1 quintal (100 kg) standing on the rails. Calculate the velocity with which the car will start traveling along the rails.

Click for Answer/Explanation

Here m= 60 kg, u1= 18 km/hr = 5 m/s, M=100 kg, u2=0

Let v be the velocity with which the car starts traveling

Now

mu1+Mu2 = (M+m)v

60×5 = 160v

v = 1.875 m/s

Question 10

A boy of mass 50 kg running 5 m/s jumps onto a 20 kg trolley traveling in the same direction at 1.5 m/s. Find their common velocity.

Click for Answer/Explanation

Here m = 50 kg, u1 = 5m/s, M = 20 kg, u2 =  1.5m/s

Now

mu1 + Mu2 = (M+m)v

50×5+20×1.5=70v

or v = 4 m/s

Now try solving these few questions by yourself. Comment your Answer in the comment box below.

Question 11.

If a constant force acts on an object of mass 15 kg for a duration of 3 s. It increases the object’s velocity from 10 m/s to 15 m/s. How much force is applied? Now, if the force was applied for a duration of 4s, what would be the final velocity of the object?

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Question 12.

A bullet of mass 40 g is horizontally fired with a velocity of 120 m/s from a gun of mass 1.5 kg. Find the recoil velocity of the gun

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Question 13

If a horizontal force of 800 N drags a box across a floor at a constant velocity, then find the force of friction that will be exerted on the box.

Question 14

A block of mass 3 kg has a velocity of u m/s. When a force of 18 N acts on the block, it reduces the velocity from u m/s to u/2 m/s after the block has covered a distance of 9 m. Find u.

Video Solution of Question 14.

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Question 15

If a force of 50 N is applied on a heavy box of 50 kg and it doesn’t move. What is the frictional force exerted on the box?

Click for Answers/Explanations

Since the box doesn’t move, the frictional force must be equal to the applied force, as friction prevents motion.

  • Applied force = 50 N
  • Box doesn’t move, so frictional force = Applied force.
  • The frictional force exerted on the box is 50 N.

Question 16.

A football of mass 700 gm moving with a velocity of 10 m/s is brought to rest by a player in 0.02 s. Find the impulse of the force and the average force applied by the player.

Click for Answers/Explanations

Given:

  • Mass of football, m = 700 gm = 0.7 kg
  • Initial velocity, u = 10 m/s
  • Final velocity, v = 0 m/s (since the football is brought to rest)
  • Time taken, t = 0.02 s

Use Formula- Impulse = change in momentum = I = m(v-u)

Final Answer:

  • Impulse = 7 Ns
  • Average Force = 350 N

Question 17.

A cricket ball of mass 500 gm is moving with a velocity of 15 m/s. A fielder catches it and brings it to rest in 0.05 seconds. Find the impulse of the force and the average force applied by the fielder.

Question 18.

A car of mass 1000 kg is initially moving at 20 m/s. The driver applies brakes and brings it to rest in 5 seconds. Calculate the impulse and the average braking force exerted by the brakes.

Question 19.

A tennis ball of mass 250 gm is struck by a racket, changing its velocity from 5 m/s to 25 m/s in 0.01 seconds. Find the impulse and the average force exerted by the racket on the ball.

Question 20.

A hockey puck of mass 200 gm slides on ice with a velocity of 8 m/s. A player stops it in 0.1 seconds by applying force. Find the impulse and the average force exerted by the player.

Question 21.

A bullet of mass 50 gm is fired from a gun at a velocity of 300 m/s. It comes to rest after hitting a wall in 0.005 seconds. Calculate the impulse and the average force exerted by the wall on the bullet.

Question 22.

Which would require a greater force- accelerating a 50 g mass at 10 m/s2 or 75 g mass at 2 m/s2?

Question 23.

What is the acceleration produced by a force of 50 N when applied on a body of mass 5 kg?

Question 24.

Find the force needed to accelerate a body of 8 kg by 7 m/s2?

Question 25.

Find the ratio of SI to cgs units of linear momentum.

Question 26.

A bus starting from rest is rolling down a hill with constant acceleration. If it travels a distance of 500 m in 25 seconds. Find the acceleration of the bus and the force acting on it. Consider the mass of the bus 5 metric tonnes.

Question 27.

A stretching force of 100 N is applied at one end of a spring balance and an equal stretching force is applied at the other end at the same time. What would be the reading on the spring balance?

Question 28.

A machine gun has a mass of 30 kg. The gun fires bullets of 35 g at the rate of 400 bullets per minute with a speed of 400 m/s. What force must be applied to the gun so that the gun is kept in position? (Ans: F= 93.3 N)

Question 29.

A car with a mass of 1200 kg is traveling at a constant velocity of 20 m/s on a straight road. Suddenly, the driver applies the brakes, and the car comes to a complete stop in 5 seconds. Calculate-

  • The initial momentum of the car
  • The deceleration (negative acceleration) of the car.
  • The force applied by the brakes to stop the car.
Click for Answer/Explanation
  • Momentum(p)=Mass(m)×Velocity(v) = 24000 kg m/s
  • To calculate the deceleration

use the following equation from the first equation of motion- v = u + at ⇒ a = (v-u)/t = – 4 m/s2

  • Force(F)=Mass(m)×Acceleration(a) = -4800 N

Note: The negative sign indicates that the force is acting in the opposite direction of motion.

Question 30.

A truck of mass 3000 kg is moving at 30 m/s. The driver applies the brakes, and the truck stops in 10 seconds. Calculate:

  1. The initial momentum of the truck.
  2. The deceleration.
  3. The force applied by the brakes.

Question 31.

A cyclist with a total mass of 80 kg (including the cycle) is moving at 10 m/s. He applies the brakes and stops in 4 seconds. Find:

The initial momentum.
The deceleration.
The force exerted by the brakes.

Question 32.

A train of mass 5000 kg is moving at 40 m/s. It slows down and comes to rest in 20 seconds due to friction and braking. Calculate:

The initial momentum of the train.
The deceleration.
The braking force.

Question 33.

A speeding car of mass 1500 kg is moving at 25 m/s. The driver suddenly brakes, and the car stops in 8 seconds. Determine:

  1. The initial momentum.
  2. The deceleration.
  3. The force exerted by the brakes.

Question 34.

A bus of mass 5000 kg is moving at 15 m/s. The driver applies brakes, bringing the bus to rest in 6 seconds. Calculate:

  1. The initial momentum of the bus.
  2. The deceleration.
  3. The force applied by the brakes.

Question 35.

A sports car of mass 1500 kg is moving at 30 m/s on a highway. The driver suddenly applies the brakes to avoid a collision. The car decelerates uniformly and comes to a stop after covering a distance of 90 meters.

Calculate:

  1. The initial momentum of the car.
  2. The acceleration (deceleration) of the car using kinematic equations.
  3. The time taken for the car to stop.
  4. The force applied by the brakes to bring the car to rest.
  5. The work done by the braking force in stopping the car.

Question 36.

A train starts from rest and accelerates uniformly at 2 m/s² for 10 seconds. It then moves at a constant speed for 20 seconds before decelerating at -3 m/s² to stop.

Find:

  1. The maximum velocity attained by the train.
  2. The total distance covered by the train.

Question 37.

A force of 20 N is applied to a 4 kg box placed on a frictionless surface. Calculate:

  1. The acceleration of the box.
  2. The velocity of the box after 5 seconds if it starts from rest.

Question 38.

A 1000 kg car moving at 20 m/s is brought to rest in 5 seconds by applying brakes. Find:

  • The acceleration (retardation) of the car.
  • The force applied by the brakes.

Question 39.

A man of 60 kg jumps out of a boat of 300 kg with a velocity of 3 m/s. Find the velocity with which the boat moves backward.

Question 40.

A car starts from rest and follows the velocity-time graph below:

time (s)-            0, 2, 4, 6, 8, 10

velocity (m/s)- 0, 4, 8, 12, 12, 0

Find:

  • The acceleration of the car in the first 6 seconds.
  • The total distance covered by the car.

Question 41.

A bus moves with a uniform velocity of 30 m/s for 5 seconds, then comes to rest in the next 10 seconds. Draw the velocity-time graph and find:

  • The acceleration while stopping.
  • The total distance traveled by the bus.

Read Also: Gravitation Class 9 Numerical with Solution

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10 thoughts on “40+ Force and Laws of Motion Class 9 Numericals”

  3. The site is very good every que has ans and which que we can do easily theres the formula to do it by ourselves I would recommend to use this site for such numericals

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